4 #include "object-store.h"
6 static int score_missing(unsigned mode)
12 else if (S_ISLNK(mode))
19 static int score_differs(unsigned mode1, unsigned mode2)
23 if (S_ISDIR(mode1) != S_ISDIR(mode2))
25 else if (S_ISLNK(mode1) != S_ISLNK(mode2))
32 static int score_matches(unsigned mode1, unsigned mode2)
36 /* Heh, we found SHA-1 collisions between different kind of objects */
37 if (S_ISDIR(mode1) != S_ISDIR(mode2))
39 else if (S_ISLNK(mode1) != S_ISLNK(mode2))
42 else if (S_ISDIR(mode1))
44 else if (S_ISLNK(mode1))
51 static void *fill_tree_desc_strict(struct tree_desc *desc,
52 const struct object_id *hash)
55 enum object_type type;
58 buffer = read_object_file(hash, &type, &size);
60 die("unable to read tree (%s)", oid_to_hex(hash));
62 die("%s is not a tree", oid_to_hex(hash));
63 init_tree_desc(desc, buffer, size);
67 static int base_name_entries_compare(const struct name_entry *a,
68 const struct name_entry *b)
70 return base_name_compare(a->path, tree_entry_len(a), a->mode,
71 b->path, tree_entry_len(b), b->mode);
75 * Inspect two trees, and give a score that tells how similar they are.
77 static int score_trees(const struct object_id *hash1, const struct object_id *hash2)
81 void *one_buf = fill_tree_desc_strict(&one, hash1);
82 void *two_buf = fill_tree_desc_strict(&two, hash2);
88 if (one.size && two.size)
89 cmp = base_name_entries_compare(&one.entry, &two.entry);
91 /* two lacks this entry */
94 /* two has more entries */
100 /* path1 does not appear in two */
101 score += score_missing(one.entry.mode);
102 update_tree_entry(&one);
103 } else if (cmp > 0) {
104 /* path2 does not appear in one */
105 score += score_missing(two.entry.mode);
106 update_tree_entry(&two);
108 /* path appears in both */
109 if (!oideq(&one.entry.oid, &two.entry.oid)) {
110 /* they are different */
111 score += score_differs(one.entry.mode,
114 /* same subtree or blob */
115 score += score_matches(one.entry.mode,
118 update_tree_entry(&one);
119 update_tree_entry(&two);
128 * Match one itself and its subtrees with two and pick the best match.
130 static void match_trees(const struct object_id *hash1,
131 const struct object_id *hash2,
137 struct tree_desc one;
138 void *one_buf = fill_tree_desc_strict(&one, hash1);
142 const struct object_id *elem;
146 elem = tree_entry_extract(&one, &path, &mode);
149 score = score_trees(elem, hash2);
150 if (*best_score < score) {
152 *best_match = xstrfmt("%s%s", base, path);
156 char *newbase = xstrfmt("%s%s/", base, path);
157 match_trees(elem, hash2, best_score, best_match,
158 newbase, recurse_limit - 1);
163 update_tree_entry(&one);
169 * A tree "oid1" has a subdirectory at "prefix". Come up with a tree object by
170 * replacing it with another tree "oid2".
172 static int splice_tree(const struct object_id *oid1, const char *prefix,
173 const struct object_id *oid2, struct object_id *result)
179 struct tree_desc desc;
180 unsigned char *rewrite_here;
181 const struct object_id *rewrite_with;
182 struct object_id subtree;
183 enum object_type type;
186 subpath = strchrnul(prefix, '/');
187 toplen = subpath - prefix;
191 buf = read_object_file(oid1, &type, &sz);
193 die("cannot read tree %s", oid_to_hex(oid1));
194 init_tree_desc(&desc, buf, sz);
201 tree_entry_extract(&desc, &name, &mode);
202 if (strlen(name) == toplen &&
203 !memcmp(name, prefix, toplen)) {
205 die("entry %s in tree %s is not a tree", name,
209 * We cast here for two reasons:
211 * - to flip the "char *" (for the path) to "unsigned
212 * char *" (for the hash stored after it)
214 * - to discard the "const"; this is OK because we
215 * know it points into our non-const "buf"
217 rewrite_here = (unsigned char *)(desc.entry.path +
218 strlen(desc.entry.path) +
222 update_tree_entry(&desc);
225 die("entry %.*s not found in tree %s", toplen, prefix,
228 struct object_id tree_oid;
229 hashcpy(tree_oid.hash, rewrite_here);
230 status = splice_tree(&tree_oid, subpath, oid2, &subtree);
233 rewrite_with = &subtree;
237 hashcpy(rewrite_here, rewrite_with->hash);
238 status = write_object_file(buf, sz, tree_type, result);
244 * We are trying to come up with a merge between one and two that
245 * results in a tree shape similar to one. The tree two might
246 * correspond to a subtree of one, in which case it needs to be
247 * shifted down by prefixing otherwise empty directories. On the
248 * other hand, it could cover tree one and we might need to pick a
251 void shift_tree(struct repository *r,
252 const struct object_id *hash1,
253 const struct object_id *hash2,
254 struct object_id *shifted,
259 int add_score, del_score;
262 * NEEDSWORK: this limits the recursion depth to hardcoded
263 * value '2' to avoid excessive overhead.
268 add_score = del_score = score_trees(hash1, hash2);
269 add_prefix = xcalloc(1, 1);
270 del_prefix = xcalloc(1, 1);
273 * See if one's subtree resembles two; if so we need to prefix
274 * two with a few fake trees to match the prefix.
276 match_trees(hash1, hash2, &add_score, &add_prefix, "", depth_limit);
279 * See if two's subtree resembles one; if so we need to
280 * pick only subtree of two.
282 match_trees(hash2, hash1, &del_score, &del_prefix, "", depth_limit);
284 /* Assume we do not have to do any shifting */
285 oidcpy(shifted, hash2);
287 if (add_score < del_score) {
288 /* We need to pick a subtree of two */
294 if (get_tree_entry(r, hash2, del_prefix, shifted, &mode))
295 die("cannot find path %s in tree %s",
296 del_prefix, oid_to_hex(hash2));
303 splice_tree(hash1, add_prefix, hash2, shifted);
307 * The user says the trees will be shifted by this much.
308 * Unfortunately we cannot fundamentally tell which one to
309 * be prefixed, as recursive merge can work in either direction.
311 void shift_tree_by(struct repository *r,
312 const struct object_id *hash1,
313 const struct object_id *hash2,
314 struct object_id *shifted,
315 const char *shift_prefix)
317 struct object_id sub1, sub2;
318 unsigned short mode1, mode2;
319 unsigned candidate = 0;
321 /* Can hash2 be a tree at shift_prefix in tree hash1? */
322 if (!get_tree_entry(r, hash1, shift_prefix, &sub1, &mode1) &&
326 /* Can hash1 be a tree at shift_prefix in tree hash2? */
327 if (!get_tree_entry(r, hash2, shift_prefix, &sub2, &mode2) &&
331 if (candidate == 3) {
332 /* Both are plausible -- we need to evaluate the score */
333 int best_score = score_trees(hash1, hash2);
337 score = score_trees(&sub1, hash2);
338 if (score > best_score) {
342 score = score_trees(&sub2, hash1);
343 if (score > best_score)
348 /* Neither is plausible -- do not shift */
349 oidcpy(shifted, hash2);
355 * shift tree2 down by adding shift_prefix above it
358 splice_tree(hash1, shift_prefix, hash2, shifted);
361 * shift tree2 up by removing shift_prefix from it
364 oidcpy(shifted, &sub2);